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Calculus Guide · Part 4

Derivatives of Transcendental Functions

The derivatives of the trig, exponential, and logarithmic functions — the short list worth memorizing, and the logic that makes it stick.

What “transcendental” means

The functions in the earlier guides — powers, polynomials, ratios of polynomials — are algebraic: built from a finite number of additions, multiplications, and roots. Transcendental functions are everything beyond that: the trigonometric functions, exponentials, and logarithms. They “transcend” algebra, and each comes with its own derivative that has to be learned rather than derived from the power rule.

The good news: the list is short, and each entry has a logic to it. This guide covers the derivatives themselves; combining them with other functions is the job of the product, quotient, and chain rules.

Trigonometric functions

f(x)f′(x)
sin(x)cos(x)
cos(x)−sin(x)
tan(x)sec²(x)

Sine and cosine chase each other in a four-step cycle that is worth memorizing outright: sin → cos → −sin → −cos → sin. Differentiating moves you one step forward, and the minus signs live on the second half of the cycle. A picture helps it stick: the sine curve is climbing steepest exactly where cosine is at its maximum, and flat exactly where cosine crosses zero — the cosine curve is the slope readout of the sine curve.

Tangent’s derivative, sec²(x), isn’t arbitrary either — it follows from applying the quotient rule to tan(x) = sin(x)/cos(x), a satisfying exercise once you’ve read the product & quotient guide. The inverse trig functions (arcsin, arccos, arctan) have derivatives that look completely different — algebraic expressions like 1/√(1−x²) — and the calculator handles all of them if you need a reference.

Exponential functions

d/dx[eˣ] = eˣ     d/dx[aˣ] = aˣ · ln(a)

The function has the most famous derivative in calculus: itself. It is the unique function (up to a constant multiple) whose rate of growth at every point equals its current value — which is exactly why e ≈ 2.718 is the natural base for modeling growth and decay, and why appears unchanged, again and again, in every derivative involving it.

Other bases pick up a correction factor: d/dx[2ˣ] = 2ˣ · ln(2). The ln(a) factor measures how far the base a is from the “natural” base e (and indeed, plugging in a = e makes the factor ln(e) = 1, recovering the clean rule).

Logarithmic functions

d/dx[ln(x)] = 1/x     d/dx[logₐ(x)] = 1/(x · ln(a))

The natural log differentiates to the reciprocal — a surprising bridge between the transcendental world and simple algebra. It matches the shape of the graph: ln(x) climbs steeply near zero (where 1/x is huge) and flattens out as x grows (where 1/x shrinks toward zero).

As with exponentials, other bases pick up an ln(a) correction in the denominator. In practice, calculus works almost exclusively with ln for exactly this reason — the formulas are cleanest in base e.

How to apply them, step by step

Differentiate f(x) = 3sin(x) + 2eˣ − ln(x):

  1. Split at the signs (sum/difference rule): 3sin(x), 2eˣ, and −ln(x).
  2. First term. Park the 3, differentiate sine: 3 · cos(x).
  3. Second term. Park the 2; is its own derivative: 2eˣ.
  4. Third term. The natural log rule, sign riding along: −1/x.
  5. Reassemble:

f′(x) = 3cos(x) + 2eˣ − 1/x

Common mistakes to avoid

  • The cosine sign slip. Writing d/dx[cos x] = sin x instead of −sin x — responsible for roughly half of all trig derivative errors. How to avoid it: recite the full cycle (sin → cos → −sin → −cos) rather than memorizing the two rules separately; the cycle keeps the signs attached to their places.
  • Using the power rule on exponentials. Writing d/dx[2ˣ] = x · 2ˣ⁻¹. The power rule applies when the variable is in the base (); when the variable is in the exponent, it is an exponential function with its own rule: 2ˣ ln(2). How to avoid it: before differentiating anything with an exponent, ask where the variable lives — base or exponent.
  • Tangling ln(x) with 1/x. Because d/dx[ln x] = 1/x, students sometimes run the relationship backwards and write d/dx[1/x] = ln(x). In fact 1/x = x⁻¹ differentiates by the power rule to −1/x². How to avoid it: rewrite 1/x as x⁻¹ before differentiating, and the power rule produces the right answer automatically.

Worked example, start to finish

Differentiate g(x) = 5eˣ + 2cos(x) − 4ln(x) + π.

Step 1 — Split into terms. 5eˣ, 2cos(x), −4ln(x), and π.

Step 2 — First term. is its own derivative: 5eˣ.

Step 3 — Second term. Cosine moves one step in the cycle, to −sin: 2 · (−sin(x)) = −2sin(x).

Step 4 — Third term. Natural log rule: −4 · (1/x) = −4/x.

Step 5 — Last term. π is a constant — no variable, derivative zero.

Step 6 — Reassemble.

g′(x) = 5eˣ − 2sin(x) − 4/x

Check your work

Try a few by hand, then verify every step with the derivative calculator — if your answer differs, the named steps show you exactly which rule to revisit: